The sum of three numbers m GP is 56. If we subtract 1.7,21 from these numbers in that order, we obtain an arithmetic progression. Find the numbers.

Explanation

given that, `a+ar+ar^2= 56`

`a(1+r+r^2)=56`

acc to question

`(ar^2-21) + ( a-1) = 2(ar-7)`

`ar^2 + a -22= 2ar -14`

`a(r^2 + 1 -2r)=8`

`(r^2+r+1)/(r^2-2r+1) = 7`

`r^2 +r+1 = 7r^2 - 14r + 7`

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