At a point 15 m away from the base of a 15 m high house, the angle of elevation of the top is

Options

A. `90^(@)`
B. `60^(@)`
C. `45^(@)`
D. `30^(@)`

Answer

C

Explanation

Let AB be the house of height 15m. Let B be the base of house and C be the point 15 m away from the base of a house. Let `'theta'` be the angle of elevation. So, in `DeltaABC`,
we have `tan theta = (AB)/(BC)=(15)/(15)=1`
`rArr tan theta = tan 45^(@) (.:' tan 45^(@)=1)`
`rArr theta = 45^(@)`