A tower of height 15 m stands vertically on the ground. From a point on the ground the angle of elevation of the top of the tower is found to be `30^(@)`. What is the distance of the point from the foot of the tower?

Options

A. `15sqrt(3)m`
B. `10sqrt(3)m`
C. `5sqrt(3)`m
D. 30m

Answer

A

Explanation

Let AB be a tower of height 15m. Let B be the point on the ground. Let `angleACB=30^(@)` be the angle of elevation. To find BC.

Let BC xm.
In `Delta ABC, tan 30^(@)=(AB)/(BC)=(15)/(x)`
`rArr (1)/(sqrt(3))=(15)/(x) rArr x=15sqrt(3))m`