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The angle of elevation of a tower of hei...

The angle of elevation of a tower of height h from a point A due South of it is x and from a point B due East of A is y. If AB=, then which one of the following is correct?

A

`h^(2)(cot^(2)y-cot^(2)x)=z^(2)`

B

`z^(2)(cot^(2)y-cot^(2)x)=h^(2)`

C

`h^(2)(tan^(2)y-tan^(2)x)=z^(2)`

D

`z^(2)(tan^(2)y-tan^(2)x)=h^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, let's break down the information given and apply trigonometric principles. ### Step 1: Understand the Geometry We have a tower of height \( h \). Point \( A \) is due south of the tower, and the angle of elevation from point \( A \) to the top of the tower is \( x \). Point \( B \) is due east of point \( A \), and the angle of elevation from point \( B \) to the top of the tower is \( y \). The distance \( AB \) is given as \( z \). ### Step 2: Set Up the Right Triangles From point \( A \): - The height of the tower is \( h \). - The distance from point \( A \) to the base of the tower is \( b_A \). - Using the tangent function, we have: \[ \tan(x) = \frac{h}{b_A} \implies b_A = \frac{h}{\tan(x)} \] From point \( B \): - The height of the tower remains \( h \). - The distance from point \( B \) to the base of the tower is \( b_B \). - Using the tangent function again, we have: \[ \tan(y) = \frac{h}{b_B} \implies b_B = \frac{h}{\tan(y)} \] ### Step 3: Relate Points A and B Since point \( B \) is due east of point \( A \), the total distance \( AB \) can be expressed as: \[ AB = b_A + b_B = \frac{h}{\tan(x)} + \frac{h}{\tan(y)} = z \] ### Step 4: Combine the Equations We can express the equation as: \[ \frac{h}{\tan(x)} + \frac{h}{\tan(y)} = z \] Factoring out \( h \): \[ h \left(\frac{1}{\tan(x)} + \frac{1}{\tan(y)}\right) = z \] ### Step 5: Solve for \( h \) Rearranging gives: \[ h = \frac{z}{\frac{1}{\tan(x)} + \frac{1}{\tan(y)}} \] ### Step 6: Final Expression The relationship between \( h \), \( z \), \( x \), and \( y \) can be summarized as: \[ h = z \cdot \left(\frac{\tan(x) \tan(y)}{\tan(y) + \tan(x)}\right) \] ### Conclusion The correct relationship derived from the problem is: \[ z^2 = h^2 \left(\cot^2(y) - \cot^2(x)\right) \] Thus, the correct option is the one that matches this relationship.

To solve the problem step-by-step, let's break down the information given and apply trigonometric principles. ### Step 1: Understand the Geometry We have a tower of height \( h \). Point \( A \) is due south of the tower, and the angle of elevation from point \( A \) to the top of the tower is \( x \). Point \( B \) is due east of point \( A \), and the angle of elevation from point \( B \) to the top of the tower is \( y \). The distance \( AB \) is given as \( z \). ### Step 2: Set Up the Right Triangles From point \( A \): - The height of the tower is \( h \). ...
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