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What is the area between the curve y =...

What is the area between the curve
`y = cos 3x, 0 le x le pi/6` and the co-ordinate axes ?

A

1 square unit

B

1/2 square unit

C

1/3 squre unit

D

1/4 square unit

Text Solution

Verified by Experts

The correct Answer is:
C

Required Area `= int_(0)^(pi//6) cos 3x dx`
`= (sin3x)/(3)|_(0)^(pi/6) = (sin3(pi/6))/(3) - sin 0`
`= 1/2 sin 'pi/2 - 0 = 1/3 (1) = 1/3` sq. unit.
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NDA PREVIOUS YEARS-DEFINITE INTEGRATION & ITS APPLICATION-DIRECTIONS
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