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What is int(2)^(8) |x-5|dx equal to ?...

What is `int_(2)^(8) |x-5|dx` equal to ?

A

`2`

B

`3`

C

`4`

D

`9`

Text Solution

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The correct Answer is:
To solve the integral \( \int_{2}^{8} |x-5| \, dx \), we need to break it down based on the definition of the absolute value function. ### Step 1: Identify the points where the expression inside the absolute value changes sign. The expression \( |x-5| \) changes sign at \( x = 5 \). Thus, we will evaluate the integral from \( 2 \) to \( 5 \) and from \( 5 \) to \( 8 \). ### Step 2: Rewrite the integral by splitting it at the point where the absolute value changes. \[ \int_{2}^{8} |x-5| \, dx = \int_{2}^{5} |x-5| \, dx + \int_{5}^{8} |x-5| \, dx \] ### Step 3: Determine the expression for \( |x-5| \) in each interval. - For \( x \) in the interval \( [2, 5] \), \( x-5 \) is negative, so \( |x-5| = -(x-5) = 5-x \). - For \( x \) in the interval \( [5, 8] \), \( x-5 \) is positive, so \( |x-5| = x-5 \). ### Step 4: Rewrite the integral with the expressions found. \[ \int_{2}^{8} |x-5| \, dx = \int_{2}^{5} (5-x) \, dx + \int_{5}^{8} (x-5) \, dx \] ### Step 5: Evaluate the first integral \( \int_{2}^{5} (5-x) \, dx \). \[ \int (5-x) \, dx = 5x - \frac{x^2}{2} \] Now, evaluate from \( 2 \) to \( 5 \): \[ \left[ 5x - \frac{x^2}{2} \right]_{2}^{5} = \left( 5(5) - \frac{5^2}{2} \right) - \left( 5(2) - \frac{2^2}{2} \right) \] Calculating this gives: \[ \left( 25 - \frac{25}{2} \right) - \left( 10 - 2 \right) = \left( 25 - 12.5 \right) - 8 = 12.5 - 8 = 4.5 \] ### Step 6: Evaluate the second integral \( \int_{5}^{8} (x-5) \, dx \). \[ \int (x-5) \, dx = \frac{x^2}{2} - 5x \] Now, evaluate from \( 5 \) to \( 8 \): \[ \left[ \frac{x^2}{2} - 5x \right]_{5}^{8} = \left( \frac{8^2}{2} - 5(8) \right) - \left( \frac{5^2}{2} - 5(5) \right) \] Calculating this gives: \[ \left( \frac{64}{2} - 40 \right) - \left( \frac{25}{2} - 25 \right) = \left( 32 - 40 \right) - \left( 12.5 - 25 \right) = -8 - (-12.5) = -8 + 12.5 = 4.5 \] ### Step 7: Combine the results of both integrals. \[ \int_{2}^{8} |x-5| \, dx = 4.5 + 4.5 = 9 \] Thus, the final answer is: \[ \int_{2}^{8} |x-5| \, dx = 9 \]

To solve the integral \( \int_{2}^{8} |x-5| \, dx \), we need to break it down based on the definition of the absolute value function. ### Step 1: Identify the points where the expression inside the absolute value changes sign. The expression \( |x-5| \) changes sign at \( x = 5 \). Thus, we will evaluate the integral from \( 2 \) to \( 5 \) and from \( 5 \) to \( 8 \). ### Step 2: Rewrite the integral by splitting it at the point where the absolute value changes. \[ \int_{2}^{8} |x-5| \, dx = \int_{2}^{5} |x-5| \, dx + \int_{5}^{8} |x-5| \, dx ...
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