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If 5 and 7 are the roots of the equation...

If 5 and 7 are the roots of the equation `|{:(x,4,5),(7,x,7),(5,8,x):}|=0`, then what is the third root ?

A

-12

B

9

C

13

D

14

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The correct Answer is:
To find the third root of the equation given by the determinant \( |{:(x,4,5),(7,x,7),(5,8,x):}|=0 \), where 5 and 7 are known roots, we will follow these steps: ### Step 1: Set Up the Determinant The determinant can be expressed as: \[ D = \begin{vmatrix} x & 4 & 5 \\ 7 & x & 7 \\ 5 & 8 & x \end{vmatrix} \] ### Step 2: Expand the Determinant We will expand the determinant using the first row: \[ D = x \begin{vmatrix} x & 7 \\ 8 & x \end{vmatrix} - 4 \begin{vmatrix} 7 & 7 \\ 5 & x \end{vmatrix} + 5 \begin{vmatrix} 7 & x \\ 5 & 8 \end{vmatrix} \] Calculating each of these 2x2 determinants: 1. \( \begin{vmatrix} x & 7 \\ 8 & x \end{vmatrix} = x^2 - 56 \) 2. \( \begin{vmatrix} 7 & 7 \\ 5 & x \end{vmatrix} = 7x - 35 \) 3. \( \begin{vmatrix} 7 & x \\ 5 & 8 \end{vmatrix} = 56 - 5x \) Substituting these back into our determinant: \[ D = x(x^2 - 56) - 4(7x - 35) + 5(56 - 5x) \] ### Step 3: Simplify the Expression Expanding and simplifying: \[ D = x^3 - 56x - 28x + 140 + 280 - 25x \] Combining like terms: \[ D = x^3 - 109x + 420 \] ### Step 4: Factor the Polynomial Given that 5 and 7 are roots, we can express the polynomial as: \[ D = (x - 5)(x - 7)(x - r) \] To find the third root \( r \), we can use polynomial division. ### Step 5: Perform Polynomial Division Dividing \( x^3 - 109x + 420 \) by \( (x - 5)(x - 7) \): 1. First, calculate \( (x - 5)(x - 7) = x^2 - 12x + 35 \). 2. Now perform the division of \( x^3 - 109x + 420 \) by \( x^2 - 12x + 35 \). Using long division: - Divide \( x^3 \) by \( x^2 \) to get \( x \). - Multiply \( x \) by \( x^2 - 12x + 35 \) to get \( x^3 - 12x^2 + 35x \). - Subtract this from the original polynomial to get \( 12x^2 - 144x + 420 \). - Divide \( 12x^2 \) by \( x^2 \) to get \( 12 \). - Multiply \( 12 \) by \( x^2 - 12x + 35 \) to get \( 12x^2 - 144x + 420 \). - Subtracting gives a remainder of 0. ### Step 6: Identify the Third Root The quotient from the division is \( x + 12 \). Therefore, the third root is: \[ x + 12 = 0 \implies x = -12 \] ### Final Answer The third root is \( \boxed{-12} \).

To find the third root of the equation given by the determinant \( |{:(x,4,5),(7,x,7),(5,8,x):}|=0 \), where 5 and 7 are known roots, we will follow these steps: ### Step 1: Set Up the Determinant The determinant can be expressed as: \[ D = \begin{vmatrix} x & 4 & 5 \\ 7 & x & 7 \\ ...
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