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Consider the following statements in res...

Consider the following statements in respect of the square matrices A and B of same order:
1. A and B are non-zero and AB = 0 `rarr` either |A| = 0 or |B| = 0
2. `AB = 0 rarr A = 0 or B = 0`
Which of the above statements is/are correct ?

A

1 only

B

2 only

C

Both 1 and 2

D

Neither 1 nor 2

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The correct Answer is:
To solve the problem, we need to analyze the two statements regarding the square matrices \( A \) and \( B \) of the same order. ### Step 1: Analyze the second statement The second statement claims: \[ AB = 0 \Rightarrow A = 0 \text{ or } B = 0 \] To evaluate this, we can consider a counterexample. Let: \[ A = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}, \quad B = \begin{pmatrix} 0 & 0 \\ 3 & 4 \end{pmatrix} \] Calculating the product: \[ AB = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix} \begin{pmatrix} 0 & 0 \\ 3 & 4 \end{pmatrix} = \begin{pmatrix} 0 & 0 \\ 0 & 0 \end{pmatrix} \] Here, \( AB = 0 \) but neither \( A \) nor \( B \) is the zero matrix. Therefore, the second statement is **not correct**. ### Step 2: Analyze the first statement The first statement claims: \[ AB = 0 \Rightarrow |A| = 0 \text{ or } |B| = 0 \] Using the property of determinants, we know: \[ |AB| = |A| \cdot |B| \] If \( AB = 0 \), then: \[ |AB| = |0| = 0 \] This implies: \[ |A| \cdot |B| = 0 \] For the product of two determinants to be zero, at least one of the determinants must be zero. Thus, we conclude: \[ |A| = 0 \text{ or } |B| = 0 \] Therefore, the first statement is **correct**. ### Conclusion - The first statement is correct. - The second statement is incorrect. Thus, the answer is that only the first statement is correct. ### Final Answer **Option A: 1 only** ---

To solve the problem, we need to analyze the two statements regarding the square matrices \( A \) and \( B \) of the same order. ### Step 1: Analyze the second statement The second statement claims: \[ AB = 0 \Rightarrow A = 0 \text{ or } B = 0 \] To evaluate this, we can consider a counterexample. Let: \[ A = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}, \quad B = \begin{pmatrix} 0 & 0 \\ 3 & 4 \end{pmatrix} \] ...
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