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|{:("6i " "-3i " "1" ),("4 " " 3i" " -1"...

`|{:("6i " "-3i " "1" ),("4 " " 3i" " -1"),("20 " "3 " " i"):}|`=x+iy then

A

3

B

2

C

1

D

0

Text Solution

Verified by Experts

The correct Answer is:
D
`|(6i,-3i,1),(4,3i,-1),(20,3,i)|`
`=6i[3i^(2)+3]+3i[4i+20]+1[12-60i]`
`=6i[-3+3]+12i^(2)+60i+12-60i`
`=-12+12=0=iy`
`therefore x=0`
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