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What is "sin"^(-1)(3)/(5)- "sin"^(-1)(4)...

What is `"sin"^(-1)(3)/(5)- "sin"^(-1)(4)/(5)` equal to ?

A

`pi//2`

B

`pi//3`

C

`pi//4`

D

`pi//6`

Text Solution

Verified by Experts

The correct Answer is:
A
`"sin"^(-1)(3)/(5)+"sin"^(-1)(4)/(5)="sin"^(-1)(3)/(5)+"cos"^(-1)(3)/(5)`
`" "("let sin"^(-1)(4)/(5)=theta rArr sin theta =(4)/(5) rArr cos theta=(3)/(5))=(pi)/(2)`
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