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For a cell reaction involvinig a two ele...

For a cell reaction involvinig a two electron change, the standard emf of the cell is found to be 0.295 V at `25^(@)` C. The equilibrium constant of the reaction at `25^(@)C` will be:

A

`1xx10^(-10)`

B

`29.5xx10^(-2)`

C

`10`

D

`1xx10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG=-nFE^(o)`
`DeltaG=-2.303RT" log "K,nFE^(o)=2.303RTlogK`
`logK=(nFE^(o))/(2.303RT)=(2xx96500xx0.295)/(2.303xx8.314xx298)`
`logK=9.97=K=1xx10^(10)`
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