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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`

A

`9.65xx10^(4)`sec

B

`19.3xx10^(4)`sec

C

`28.95xx10^(4)sec`

D

`38.6xx10^(4)`sec

Text Solution

Verified by Experts

The correct Answer is:
B
Faraday's law
Equivalent of `H_2` produced `=(1xxt(sec))/(9)`
`0.01xx2=(10xx10^(-3)t)/(96500)=96500xx2=t`
`19.3xx10^(4)sec=1`.
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Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 mA current. The time required to liberate 0.01 mole of H_2 gas at the cathode is : (1f= 96500C mol^(-1)

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