For the following cell,
`Zn(s)|ZnSO_(4)(aq)||CuSO_(4)(aq)||Cu(s)`
When the concentration of `Zn^(2+)` is 10 times the concentration of `Cu^(2+)`, the expression for `DeltaG`
(in J `"mol"^(-1)`)
[F is Faraday constant, R is gas constant] T is temperaure, `E^(@)("cell")=1.1V`

Options

A. 2.303RT+1.1F
B. 1.1F
C. 2.303RT-2.2F
D. `-2.2F`

Answer

C

Explanation

`DeltaG=DeltaG^(o)+2.303RTlog_(10)Q,Q=([Zn^(2+)])/([Cu^(2+)])`
`=-2F(1.1)+2.303RTlog_(10)10`
`=2.303RT-2.2F`
Given
`E_(Cl_(2)//Cl^(-))^(o)=1.36V,E_(Cr^(3+)//Cr)^(o)=-0.74V`
`E_(Cr_(2)O_(7)^(2-)//Cr_(3+))^(o)=1.33V,E_(MnO_(4)^(-))^(o)//Mn^(2+)=1.51V`