Which of the following group of elements eliminates electron easily

Options

A. N, P, As
B. O, S, Se
C. Li, Na, K
D. Cl, Ba, I

Explanation

To determine which group of elements eliminates electrons easily, we need to analyze the groups of elements provided in the options. The ability of an element to eliminate or lose electrons is closely related to its electronic configuration and its position in the periodic table.

### Step-by-Step Solution:

1. **Understanding Electron Elimination**:
- Electron elimination refers to the ability of an atom to lose electrons easily. This is often seen in metals, which tend to lose electrons to achieve a stable electronic configuration similar to that of noble gases.

2. **Identifying the Groups**:
- The question mentions the following groups:
1. Nitrogen, Phosphorus, Arsenic (Group 15)
2. Oxygen, Sulfur (Group 16)
3. Lithium, Sodium, Potassium (Group 1)
4. Chlorine, Barium (Group 17 and Group 2)

3. **Analyzing Group 1 Elements (Lithium, Sodium, Potassium)**:
- These elements belong to the alkali metals group.
- They have one electron in their outermost shell, which they can easily lose to achieve a stable noble gas configuration (e.g., Lithium loses 1 electron to become like Helium, Sodium loses 1 electron to become like Neon, and Potassium loses 1 electron to become like Argon).
- Therefore, this group eliminates electrons very easily.

4. **Analyzing Other Groups**:
- **Group 15 (Nitrogen, Phosphorus, Arsenic)**: These elements tend to gain or share electrons rather than lose them to achieve stability.
- **Group 16 (Oxygen, Sulfur)**: Similar to Group 15, these elements typically gain electrons to achieve a stable configuration.
- **Group 17 (Chlorine)**: Chlorine tends to gain an electron to achieve stability, while Barium (Group 2) can lose electrons, but it is not as easily as the alkali metals.

5. **Conclusion**:
- The group that eliminates electrons easily is **Lithium, Sodium, Potassium (Group 1)**.

### Final Answer:
**Lithium, Sodium, Potassium (Group 1)** eliminates electrons easily.

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