The number of bacteria in a certain culture doubles every hour. If there were 60 bacteria present in the culture originally, how many bacteria will be present at the end of 2nd hour, 4th hour and nth hour?

Explanation

It is given that the number of bacteria doubles every hour.Therefore, number of bacteria after every hour will form a G.P.
Here, `a=60`, `r =2`
`a_3=ar^2=60(2)^2=240`
Therefore, the number of bacteria at the end of second hour will be 240.
`a_5=ar^4=60(2)^4=960`
The number of bacteria at the end of fourth hour will be 960.
`a_n+1=ar^n=60(2^n)`
Thus, the number of bacteria at the end of `n^(th)` hour will be `60(2^n)`.