Dimensional formula of mutual inductance is …….

Options

A. `M^1 L^2 T^(-2) A^(-2)`
B. `M^1 L^2 T^(-2) A^(-1)`
C. `M^1 L^(-2) T^2 A^2`
D. `M^(-1) L^(-2) T^2 A^(-1)`

Answer

A

Explanation

Mutual inductance,
`M=(|epsilon|)/(dI//dt) " " (because |epsilon| =M (dI)/(dt))`
Unit of `M=V/(A//S) =(V.S)/A`
`=(J.S)/(C.A)( because V=J/C)`
`=(J.S)/(A.S.A)(because C=A.S)`
Unit of `M=JA^(-2)`
`[M]=M^1 L^2 T^(-2) A^(-2)`