One mole of an ideal gas at 300 K expand...

One mole of an ideal gas at 300 K expands from V to 2V volume, then work done W in this process will be …

300 Rln2

600 Rln2

300n2

600ln2

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The correct Answer is:

Work done in isothermal process,
`W=nRT ln (V_2/V_1)`
n=1 , `V_2=2V_1`, T=300 K
`therefore W=Rxx300 ln ((2V_1)/V_1)`
=300 Rln 2

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