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A regular hexagon of side 10 cm has a ch...

A regular hexagon of side 10 cm has a charge `5 muC` at each of its vertices. Calculate the potential at the centre of the hexagon.

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Here charge on each vertex of hexagon q = 5`mu C = 5 xx 10^(-6) C`
Side of hexagon r = 10 cm=0.1 m
It is clear that distance of hexagon centre O from any of the vertices of
hexagon = r = 0.1 m
`:.` Potential at centre of hexagon `V = 6 xx (1/(4piepsi_0).q/r)`
` = (6 xx 9 xx 10^9 xx 5 xx 10^(-6))/0.1 = 2.7 xx 10^6V`
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