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See the figure here. We have two hollow ...

See the figure here. We have two hollow thin spherical shells A and B of radii R, and R, respectively. Initially as shown in Fig. (i) shell B has a charge + Q which is uniformly distributed over its outer surface but shell B has no charge. At a particular instant the two spherical shells are connected by a thin copper wire as shown in Fig. (ii). After a couple of minutes two spherical shells A and B are disconnected again as shown in Fig. (iii).

Now answer the following questions :
What is the ratio of final electric potentials of shell A and shell B ?

Text Solution

Verified by Experts

When two spherical shells are connected, electric charge flows from shell A to shell B till the two acquires a common potential V. So, we have
`V_A/V_B = V/V =1/1`
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U-LIKE SERIES-ELECTROSTATIC POTENTIAL AND CAPACITANCE -CASE BASED/SOURCE-BASED INTEGRATED QUESTIONS
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