A dipole is present in an electrostatic field of magnitude `10^6 NC^(-1)`. If the work done in rotating it from its position of stable equilibrium to its positionof unatable equilibriumequals `2 xx 10^(-23) J`,find the magnitude of the dipole moment of this dipole.

Explanation

Here `E = 10^6N C^(-1), theta_1 = 0^@, theta_2 = 180^@` and work done in rotating the dipole `W = 2 xx 10^(-23)J`,
From the relation `W = pE (costheta_1 - cos theta_2),` we have
` 2 xx 10^(-23) = p xx 10^6 xx [ (1) - (-1)] = 2pxx10^(6) rArr p = 10^(-17) C-m`