Two point charges, `q_1 = 10 xx 10^(-8) C and q_2 = -2 xx 10^(-8) C`, are separated by a distance of 60 cm in air.
Also calculate the electrostatic potential energy of the system.

Explanation

Here `q_1 = + 10 xx 10^(-8)C and q_2 = - 2 xx 10^(-8) C` and distance between them r = 60 cm = 0.6m
Electrostatic potential energy of the system
`u = (q_1q_2)/(4pi epsi_0.r) = ((10 xx 10^(-8)) xx (-2 xx 10^(-8)) xx 9 xx 10^(9))/0.6 = -3 xx 10^(-5)J`