Find equivalent capacitance between A and B in the combination given below. Each capacitor is of `2 muF` capacitance.

Explanation

The arrangement of capacitors can be redrawn as shown in Fig., where `C_1 = C_2 = C_3 = C_4 = C_5 = 2muF`.
Capacitane C. for parallel combination `C_2, C_3 and C_4` is :
`C. = C_2 + C_3 + C_4 = 2 + 2 + 2 =6muF`
Since `C_1,C. andC_5` are in series combination is given by the relation :
`1/C = 1/C_1 + 1 /(C.) + 1/C_5 = 1/2 + 1/6 + 1/2 = 7/6 rArr 6/7 muF`