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Calculate the energy released in MeV in ...

Calculate the energy released in MeV in the following nuclear reaction :
`" "_(92)^(238)U to" "_(90)^(234)Th + " "_(2)^(4)He + Q`
mass of `" "_(92)^(238)U = 238.05079 u`, mass of `" "_(90)^(234)Th = 234.043630 u`, mass of `" "_(2)^(4)He = 4.00260 u`, `1 u=931.5 MeV/c^(2)`.

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Energy released in the reaction `Q= [m (" "_(92)^(238)U) -m (" "_(90)^(234)Th) -m (" "_(2)^(4)He)]c^(2) =(238.05079 - 234.04363-4.00260) u xx c^(2)= (0.00456 u). c^(2) = 0.00456 xx 931.5 MeV= 4.25 MeV`.
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Calculate the energy released in MeV in the following nuclear reaction : ._(92)^(238)Urarr._(90)^(234)Th+._(2)^(4)He+Q ["Mass of "._(92)^(238)U=238.05079 u Mass of ._(90)^(238)Th=234.043630 u Massof ._(2)^(4)He=4.002600 u 1u = 931.5 MeV//c^(2)]

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From the following nuclei select the isotopes and isobars : ""_(92)^(238)U, ""_(90)^(234)Th, ""_(92)^(234)U, ""_(91)^(234)Pa .

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