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An enclosure of volume 3 litre contains ...

An enclosure of volume `3` litre contains `16g` of oxygen, `7 g` of nitrogen and `11 g` of carbon - di-oxide at `27^(@)C`. The pressure exerted by the mixture is approximately
`[R = 0.0821 lit "atm mole"^(-1) K^(-1)]`

Text Solution

Verified by Experts

`because P=n((RT)/(V))=(m)/(M)xx(RT)/(V)`
and `P=P_(1)+P_(2)+P_(3)`
`therefore P=(RT)/(V)[(m_(1))/(M_(1))+(m_(2))/(M_(2))+(m_(3))/(M_(3))]`
`therefore P=(RT)/(V)[(16)/(32)+(7)/(28)+(11)/(44)]=(RT)/(V)[1]`
`therefore P=(RT)/(V)=(8.3xx300)/(3xx10^(-3))=8.3atm[because 1" litre"=10^(-3)m^(3)]`
Hence pressure = 8.3 atmosphere
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