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A gas cylinder has walls that can bear a...

A gas cylinder has walls that can bear a maximum pressure of `1.0xx10^(6)Pa`. It contains a gas at `8.0xx10^(5)Pa` and `300K`. The cylinder is steadily heated. Neglecting any change in the volume calculate the temperature at which the cylinder will break.

A

325 K

B

350 K

C

375 K

D

400 K

Text Solution

Verified by Experts

The correct Answer is:
C
Using gas law, `=(P_("max")V)/(T_("max"))=(P_(0)V)/(T_(0))`
Here volume of the container is constant,
So, `T_("max")=((P_("max"))/(P_(0))).T_(0)=((1xx10^(6)kPa)/(8xx10^(5)kPa))xx300K=375K`
The cylinder will burst at 375 K.
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