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Two perfect gases at absolute temperatur...

Two perfect gases at absolute temperature `T_(1) and T_(2)` are mixed. There is no loss of energy. The masses of the molecules are `m_(1) and m_(2)`. The number of molecules in the gases are `n_(1) and n_(2)`. The temperature of the mixture is

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By law of conservation of energy,
`n_(1)E_(1)+n_(2)E_(2)=(n_(1)+n_(2))E`
or `n_(1)((3k_(B)T_(1))/(2))+n_(2)((3k_(B)T_(2))/(2))=(n_(1)+n_(2))((3k_(B)T)/(2))`
or `n_(1)T_(1)+n_(2)T_(2)=(n_(1)+n_(2))TorT=(n_(1)T_(1)+n_(2)T_(2))/(n_(1)+n_(2))`
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