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The average kinetic energy of one molecu...

The average kinetic energy of one molecule of an ideal gas at `27^@C` and 1 atm pressure is [Avogadro number `N_A=6.023xx10^(23)` ]

A

`3.1xx10^(-20)J`

B

`3.5xx10^(-21)J`

C

`5.3xx10^(-18)J`

D

`6.21xx10^(-21)J`

Text Solution

Verified by Experts

The correct Answer is:
D
Average kinetic energy
`=(3)/(2)k_(B)T=(3)/(2)(1.38xx10^(-23))(300)=6.21xx10^(-21)J`
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