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At 27^(@)C temperature, the kinetic ener...

At `27^(@)C` temperature, the kinetic energy of an ideal gas is `E_(1^.)` If the temperature is increassed to `327^(@)C,` then the kinetic energy will be

A

`(E_(1))/(2)`

B

`(E_(1))/sqrt(2)`

C

`sqrt(2)E_(1)`

D

`2E_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Kinetic energy of an ideal gas, `E_(K)=(3)/(2)RTorE_(K)propT`
`therefore E_(327)=E_(27)((327+273))/((27+273))=2E_(27)=2E_(1)`
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