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The escape velocity of an object from th...

The escape velocity of an object from the earth depends upon the mass of the earth ( M ), its mean density `(rho)`, its radius ( R ) and the gravitational constant ( G ). Thus the formula for escape velocity is

A

`v_c = R sqrt((8pi)/(3) G rho)`

B

`v_e = M ((8pi)/(3) GR)`

C

`v_e = sqrt(2GMR)`

D

`v_e =sqrt( (2GM)/(R^2))`

Text Solution

Verified by Experts

The correct Answer is:
A

Escape velocity `v_e = sqrt( (2GM)/(R )) = sqrt((2G)/( R) 4/3 pi R^3 rho) `
` = sqrt( (8pi)/(3) G rho R^2) = R sqrt( (8pi)/(3) G rho)`
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