A satellite is launched into a circular orbit of radius 'R' around earth while a second satellite is launched into an orbit or radius 1.02 R. The percentage difference in the time periods of the two satellites is

Options

A. 0.007
B. 0.01
C. 0.015
D. 0.03

Answer

D

Explanation

According to Kepler.s third law
`T^2 prop R^3 " or " Tprop R^(3//2)`
` therefore T_2/T_1 = ((1.02 R)/( R))^(3//2) = 1.03 " or " T_2 = 1.03 T_1`
` therefore ` % difference ` = (T_2 - T_1)/(T_1) xx 100% = 3%`