The escape velocity for a planet is `v_e`. A particle is projected from its surface with a speed `v`. For this particle to move as a satellite around the planet.

Options

A. `(v_e)/(2) lt v lt v_e`
B. `(v_e)/(sqrt2) lt v lt v_e`
C. `v_e lt v lt sqrt2 v_e`
D. `(v_e)/(sqrt2) lt v lt (v_e)/(2)`

Answer

B

Explanation

For a satellite orbiting very close to the earth.s surface, the orbital velocity = `sqrt(Rg)` .
This is equal to the velocity of projection and is the minimum velocity required to be in an orbit, if `v gt v_e` then the satellite will escape from earth.s gravitational pull and will not orbit around the earth
where `v_e = sqrt(2g R) = sqrt2v therefore (v_e)/(sqrt2) lt v lt v_e `