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Work done by the system in closed path A...

Work done by the system in closed path ABCA, as shown in figure is

A

zero

B

`(V_(1) - V_(2))(P_(1) - P_(2))`

C

`((P_(2) - P_(1))(V_(2) - V_(1)))/(2)`

D

`((P_(2) + P_(1))(V_(2) - V_(1)))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Work done = area of `Delta ABC`
`= (AC xx BC)/(2) = ((P_(2) - P_(1))(V_(2)-V_(1)))/(2)`
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