Starting with the same initial conditions, an ideal gas expands from volume `V_(1)` to `V_(2)` in three different ways. The work done by the gas is `W_(1)` if the process is purely isothermal, `W_(2)` if purely isobaric and `W_(3)` is purely adiabatic. Then

Options

A. `W_(2) gt W_(1) gt W_(3)`
B. `W_(3) gt W_(1) gt W_(1)`
C. `W_(1) gt W_(2) gt W_(3)`
D. `W_(1) gt W_(3) gt W_(2)`

Answer

A

Explanation

Three given processes are shown in the P-V graphs.
As work done by the gas = area under the P-V graph
`because ("Area")_(2) gt ("Area")_(1) gt ("Area")_(3)`
`:. W_(2) gt W_(1) gt W_(3)`