The volume of one mole of an ideal gas changes from V to 2V at temperature 300 K. If R is universal gas constant, then work done in this process is

Options

A. 300 Rln2
B. 600 Rln2
C. 300 ln2
D. 600 ln2

Answer

A

Explanation

Working done in an isothermal process
`W = nRT ln ((V_(2))/(V_(1)))`
Here, `n = 1 mol, T = 300 K, V_(1) V` and `V_(2) = 2V`
`:. W = 1 xx R xx 300 ln ((2V)/(V)) = 300 R ln 2`