The temperature `T_(1)` and `T_(2)` of heat reservoirs in the ideal Carnot engine are `1500^(@)C` and `500^(@)C` respectively. If `T_(1)` increases by `100^(@)C`, what will be the efficiency of the engine ?

Options

A. `62%`
B. `59%`
C. `65%`
D. `100%`

Answer

B

Explanation

Here, `T_(1) = 1500 + 100 = 1600^(@)C = 1600 + 273 1873 K`
`T_(2) = 500^(@)C = 500 + 273 = 773 K`
`:. eta = 1 - (T_(2))/(T_(1)) = 1 - (773)/(1873) = (1100)/(1873) = (1100)/(1873) xx 100% = 59%`