An ideal gas hea engine operates in a Carnot cycle between `227^(@)C` and `127^(@)C`. It absorbs 6 kcal of heat at higher temperature. The amount of heat in kcal rejected to sink is

Options

A. 4.8
B. 2.4
C. 1.2
D. `6.0`

Answer

A

Explanation

Here, `T_(1) = 227^(@)C = 227 + 273 = 500 K`
`T_(2) = 127^(@)C = 127 + 273 = 400 K, Q_(1) = 6 kcal`
As `(Q_(2))/(Q_(1)) = (T_(2))/(T_(1)) :. (Q_(2)) = (T_(2))/(T_(1))Q_(1) = (400 K)/(500 K) xx 6 kcal = 4.8 kcal`