Explain the action of conc. HCl on KMnO(...

Explain the action of conc. `HCl` on `KMnO_(4)` crystals.

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When `KMnO_(4)` is treated with conc. `HCl` Chlorine is liberated.
`2KMnO_(4)+16HCl rarr 2KCl+2MnCl_(2)+8H_(2)O+5Cl_(2)`

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HI can not prepared by the action of conc. H_2SO_4 on KI because

HI is stronger than `H_2SO_4`

HI is more volatile than `H_2SO_4`

`H_2SO_4` also oxidises HI so formed, to `I_2`

`H_2SO_4` forms complex with HI.

carbon monoxide

carbon dioxide

carbon suboxide

bicarbonate ion