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A brown ring is formed in the ring test ...

A brown ring is formed in the ring test for NOg ion. It is due to the formation of

A

`[Fe(H_(2)O)_(5) (NO)]^(2+)`

B

`FeSO_(4).NO_(2)`

C

`[Fe(H_(2)O)_(4)(NO)_(2)]^(2+)`

D

`FeSO_(4).HNO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`[Fe(H_(2)O)_(6)]^(2+) + NO to underset("Brown ring")([Fe(H_(2)O)_(5)(NO)]^(2+) + H_(2)O)`
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