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If there were only one type of charge in...

If there were only one type of charge in the universe, then

A

`oint_(S)vecE.dvecS ne 0` on any surface

B

`oint_(s)vecE.dvecS=0` if the charge is outside the surface,

C

`oint_(s)vecE.dvecS` could not be defined

D

`oint_(S)vecE.dvecS=q/epsilon_(0)` if charges of magnitude q were inside the surface.

Text Solution

Verified by Experts

The correct Answer is:
C, D
If charge is outside the surface, then charge enclosed q = 0.
Hence, `phi =0`, according to Gauss.s law.
From Gauss.s law: `oint_(s)vecE.dvecS=q/epsilon_(0)`
Hence, option (D) is correct.
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