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A loop ABCDEFA of straight edges has a s...

A loop ABCDEFA of straight edges has a six corner points A(0, 0, 0), B(5, 0, 0), C(5, 5, 0), D(0, 5, 0), E(0, 5, 5), F(0, 0, 5). The magnetic field in this region is `vecB=(3hati + 4hatk)T`. The quantity of the flux through the loop ABCDEFA (in Wb) is ......

A

350

B

175

C

100

D

75

Text Solution

Verified by Experts

The correct Answer is:
B

Magnetic flux
`phi = vecA.vecB`
`therefore phi = (vecA_(x) + vecA_(z))(vecB_(x)+vecB_(z))`
`=(25hati + 25hatk).(3hati + 4hatk)`
`therefore phi = 175 Wb`
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