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At a place horizontal component of earth...

At a place horizontal component of earth's magnetic field is `sqrt(3)` times its vertical component. The magnetic dip angle at the place is ...... radian.

A

`0`

B

`(pi)/(2) "rad"`

C

`(pi)/(3) "rad"`

D

`(pi)/(6) "rad"`

Text Solution

Verified by Experts

The correct Answer is:
D
`B_h= sqrt(3) B_v`
but `tan phi = (B_v)/( B_h)`
`therefore tanphi = (1)/(sqrt(3))`
`therefore phi = tan^(-1) ((1)/(sqrt3)) " "therefore = (pi)/(6) "rad"`
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