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The horizontal component of earth's magn...

The horizontal component of earth's magnetic field is `3 xx 10^(-4)` T. The magnetic dip angle is 45°. Find the vertical component.

A

`sqrt(3) xx 10^(-4)` T

B

`3 xx 10^(-4)` T

C

`(1)/(sqrt(3)) xx 10^(-4) ` T

D

`10^(-5)` T

Text Solution

Verified by Experts

The correct Answer is:
B
For dip angle
`tan phi = (B_v)/( B_h) " "[phi = 45^(@) , B_(h) = 3 xx 10^(-4) ]`
`therefore B_(V) = tan phi xx B_(h) `
`= tan 45^(@) xx 3 xx10^(-4)`
`= 1 xx 3 xx 10^(-4) " "[tan 45^(@) =1]`
`= 3 xx 10^(-4)` T
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KUMAR PRAKASHAN-MAGNETISM AND MATTER-SECTION D Multiple Choice Questions (MCQs) (MCQs From .DARPAN. Based On Textbook) The Earth.s Magnetism
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  2. At a place of the Earth, horizontal component of magnetic field is equ...

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  3. At a place horizontal component of earth's magnetic field is sqrt(3) t...

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  7. The horizontal component of earth's magnetic field is 3 xx 10^(-4) T. ...

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  8. The magnetic dip angle at two places are 30° and 45°. Calculate ratio ...

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  10. At a place on earth the horizontal component of earth's magnetic field...

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  11. The total intensity of the magnetic field of the earth at equator is 6...

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  14. At any place on the earth, the angle between the magnetic meridian and...

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  15. Write the unit of magnetic dipole moment.

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  16. What is the maximum value of angle of dip ?

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  17. What is the formula of angle of dip ?

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  18. At which place magnetic dip angle is maximum ?

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