The diagonals of a parallelogram are vectors `vecA and vecB`. If `vecA=5hati-4hatj+3hatk and vecB=3hati-2hatj-hatk`. Calculate the magnitude of area of this parallelogram.

Explanation

When `vecA and vecB` are the diagonals of a parallelogram, then its
Area `=1/2|vecAxxvecB|=1/2|(hati,hatj,hatk),(5,-4,3),(3,-2,-1)|`
`=1/2|hati(4+6)-hatj(5-9) +hatk(-10+12)|`
`1/2|10hati+14hatj+2hatk|=1/2sqrt((10)^(2)+(14)^(2)+(2)^(2))`
`=1/2 sqrt(300) = 10/2 sqrt(3) = 5sqrt3` unit