Home
Class 11
PHYSICS
A drunkard is walking along a straight r...

A drunkard is walking along a straight road. He takes five steps forward and three steps backward and so on. Each step is `1 m` long and takes `1 s`. There is a pit on the road `11 m`, away from the starting point. The drunkard will fall into the pit after.

A

21 s

B

29 s

C

31 s

D

41 s

Text Solution

Verified by Experts

The correct Answer is:
B
Displacement in first cight steps `= 5 m - 3m = 2m`
Time taken for first eight steps = 8 s
Time taken by drunkard to cover first six metres of journey
`=(8)/(2) xx 6 = 24 s`
If the drunkard takes 5 steps more, he will fall into the pit so the time taken by the drunkard to cover last five steps - 5 s.
Total time taken `=24 s = 5s = 29 s`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    MTG GUIDE|Exercise Topicwise Practice Questions (SPEED AND VELOCITY)|9 Videos

  • KINEMATICS

    MTG GUIDE|Exercise Topicwise Practice Questions (ACCELERATION)|12 Videos

  • KINEMATICS

    MTG GUIDE|Exercise AIPMT/ NEET MCQs|31 Videos

  • GRAVITATION

    MTG GUIDE|Exercise AIPMT/NEET MCQS|32 Videos

  • LAWS OF MOTION

    MTG GUIDE|Exercise AIPMT /NEET (MCQ)|24 Videos

Similar Questions

Explore conceptually related problems

A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, and again takes 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. Determine how long the drunkard takes to fall into a pit 13 m away from the start.

A drunkard man walking in a narrowlane takes (5) steps forward and 3 steps backward each stepe of (1) m ling, per second and os on. Determine how long the drunkard takes to fall in a pot 15 m away from the start.

Knowledge Check

  • A frog walking in a narrow lane takes 5 leaps forward and 3 leaps backward, then again 5 leaps forward and 3 leaps backward, and so on. Each leap is 1 m long and requires 1 s . Determine how long the frog takes to fall in a pit 13 m away from the starting point.

    A
    35 s
    B
    36 s
    C
    37 s
    D
    38 s

  • A man takes a step forward with probability 0.4 and backward with probability 0.6. The probability that at the end of eleven steps he is one step away from the starting point is

    A
    `(2^5 .3^5)/(5^(10))`
    B
    `462 xx ((6)/(25))^5`
    C
    `231 xx (3^5)/(5^(10))`
    D
    none of these

    • Similar Questions

    Explore conceptually related problems

    A drunkard waking in a barrow lane takes 5 steps forward and 3 steps backward, followed again 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s . Determine how long the drunkard takes to fall in a pit 13 m away from start.

    A drunkard waking in a borrow lane takes 6 steps forward and 4 steps backward, following againg 6 steps forward and 4 steps backward and so on Each step is 1 m long and requires 1s . Determine how long the drunkard takes to fall in a pit 15 m away from the start.

    A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1m long and requires 1s. Plot the x-t graph of his motion. Determine graphically or otherwise how long the drunkard takes to fall in a pit 9 m away from the start.

    A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. Plot the x -t graph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start

    A drunkard moves on a straight road such that he takes 7 steps forward and 2 steps backward in each cycle. If the stride length of each step is 1 feet and the drunkard moves with a speed 2 feet/s in forward direction and 4 feet/s in backward direction, then the time after which the drunkard will fall into a pit 11 feet further from his starting point is

    A man takes a step forward with probability 0.4 and backward with probability 0.6. Find the probability that at the end of 5 steps,he is one step away from the starting point.

    Home
    Profile