A boy is runing on the plane road with velocity v with a long hollow tube in his hand. The water is falling vertically downwards with velocity u. At water angle to the verticaly, he must inclined the tube the water drops enter it without touching its sides ?

Options

A. `tan^(-1) (v/u)`
B. `sin^(-1) (v/u)`
C. `tan^(-1) (u/v)`
D. `cos^(-1) (v/u)`

Answer

B

Explanation

Velocity of water with respect to boy is given by `vecv_(wb)` and its inclination with vertical is given by
`tan theta =v/u`
`:.theta = tan^(-1) (v/u)`