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Two particles A and B get 4m closer each...

Two particles A and B get 4m closer each second while traveling in opposite direction They get 0.4 m closer every second while traveling in same direction. The speeds of A and B are respectively :

A

`2.2 ms ^(-1) and 0.4 ms ^(-1)`

B

`2.2 ms ^(-1) and 1.8 ms ^(-1)`

C

`4 ms ^(-1) and 0.4 ms ^(-1)`

D

`2.2 ms ^(-1) and 4 ms ^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
If u and v are the speeds of A and B respectively , then
`u +v = 4ms^(-1) and u - v = 0.4 ms^(-1)`
Adding , we get `2u = 4.4 ms ^(-1) " or " u = 2.2 ms^(-1)`
`:. V = 1.8 ms^(-1)`
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