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((y-1)-(1)/(2)(y-1)^(2)+(1)/(3)(y-1)^(3)...

`((y-1)-(1)/(2)(y-1)^(2)+(1)/(3)(y-1)^(3)-....oo)/((a-1)-(1)/(2)(a-1)^(2)+(1)/(3)(a-1)^(3)-....oo)=`

A

`log_(y)a`

B

`log_(a)y`

C

`log_(a)(y//a)`

D

`log_(e )(a//y)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • e^([(x-1)-(1)/(2)(x-1)^(2)+(1)/(3)(x-1)^(3)-(1)/(4)(x-1)^(4)+………oo])=

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  • 1/(2!)-1/(3!)+1/(4!) .....oo =

    A
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    (1+(2^2)/(2!)+(2^4)/(3!)+(2^6)/(4!)+.....oo)/(1+(1)/(2!)+(2)/(3!)+(2^2)/(4!)+.....oo) =

    Observe the following lists {:("List-I","List-II"),((A) 1-(1)/(2)+(1)/(3)-(1)/(4)+(1)/(5)+...oo,(1)(2)/(3)+ (1)/(2)log2),((B)(1)/(5)+(1)/(2.5^(2))+(1)/(3.5^(3))+...oo,(2)log_(e )2),((C )(1)/(n+1)+(1)/(2(n+1)^(2))+(1)/(3(n+1)^(3))...oo,(3)-log_(e )((4)/(5))),((D)1+(1)/(3.3^(3))+(1)/(5.3^(5))+...oo,(4)log_(e )((5)/(4))),(,(5)-log_(e )(1-(1)/(n+1))):} The correct match for List - I from List -II is

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