The mean of a data set consisting of 20 observation is 40. If one observation 53 was wrongly recorded as 33, then the correct mean will be

Options

A. `(((16.2)^(9) xx 21.9)/(12.9))^(1//10)`
B. `(((16.2)^(10) xx 21.9)/(12.9))^(1//10)`
C. `(((16.2)^(10) xx 12.9)/(21.9))^(1//10)`
D. `(((16.2)^(11) xx 21.9)/(21.9))^(1//11)`

Answer

B