Home
Class 12
MATHS
f(x) = x^(2) - 1 in [-1,1]...

`f(x) = x^(2) - 1` in [-1,1]

Text Solution

Verified by Experts

The correct Answer is:
c=0
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MEAN VALUE THEOREMS

    AAKASH SERIES|Exercise EXERCISE|28 Videos

  • MATHEMATICAL REASONING

    AAKASH SERIES|Exercise Practice Exercise|21 Videos

  • MEASURES OF DISPERSION (STATISTICS)

    AAKASH SERIES|Exercise Practice Exercise|54 Videos

Similar Questions

Explore conceptually related problems

f(x) = (x^(2) - 1 ) (x - 2) in [-1, 2]

If A ={1,2,3,4} and f: A to R is a function defined by f (x) = (x ^(2) - x +1)/(x +1), then find the range of f.

Knowledge Check

  • Let f(x)=x^(2)- x+1, x ge 1//2 , then the solution of the equation f^(-1)(x)=f(x) is

    A
    `x=1`
    B
    `x=2`
    C
    `x = 1/2`
    D
    `x=0`

  • Let f(x)=(x+1)^(2)-1, x ge -1 . Then the set {x:f(x)=f^(-1)(x)} is

    A
    `{0,-1,(-3 pm i sqrt(3))/(2), (-3-i sqrt(3))/(2)}`
    B
    `{0,1,-1}`
    C
    `{0,1}`
    D
    empty

  • If f(x) = {{:(2x-1, if, x gt 1),(x^(2)+1, if, -x le x le 1):} and if (f(1) + f(3) + f(x))/(f(2) + f(-1) + f(1//2))=32/25 , then x=

    A
    1
    B
    0
    C
    4
    D
    `-2`

    • Similar Questions

    Explore conceptually related problems

    If f(x) = {:{(x^(2), x le 1), (2x -1, x gt 1):} , then find Lt_(x to 1+) f(x) and Lt_(x to 1-)f(x) . Does Lt_(x to 1) f(x) exist ?

    If f(x)=x^(2)," find "(f(1.1)-f(1))/((1.1-1))

    If f(x)=(x+1)^(2)-1, x ge -1 then the set S={x, f(x)=f^(-1)x} is

    Let f(x) = x + 1/(2x + 1/(2x + 1/(2x + ....oo))) " then " sqrt((f(50) f^'(50))/(2)) =

    If f(x) = x tan^(-1) x, " then " lim_(x to 1) (f(x) - f(1))/(x-1) equals to

    Home
    Profile