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Origin is the centre of a circle passing...

Origin is the centre of a circle passing through the vertices of an equilateral triangie whose median is of length 3a then the equation of the circle is

A

`x^(2)+y^(2)=a^(2)`

B

`x^(2)+y^(2)=2a^(2)`

C

`x^(2)+y^(2)=3a^(2)`

D

`x^(2)+y^(2)=4a^(2)`

Text Solution

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The correct Answer is:
D
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AAKASH SERIES-CIRCLES-EXERCISE II
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  6. If the two circles x^(2)+y^(2)+2gx+c=0 and x^(2)+y^(2)-2fy-c=0 have eq...

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  7. Centre and radius of the circle with segment of the line x+y=1 cut off...

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  8. The line x+y=1 cuts the coordinate axes at P and Q and a line perpendi...

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  9. The equation of the circle passing through (2, 0) and (0, 4) and havin...

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  10. The abscissae of two points A and B are the roots of the equation x^(2...

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  11. If the circles described on the line joining the points (0,1) and (alp...

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  12. A rod AB of length 4 units moves horizontally with its left end A alwa...

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  13. A line segment AM=a moves in the XOY plane such that AM is parallel to...

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  14. Locus of centroid of the triangle whose vertices are (a cos ...

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  15. A circle of constant radius 3k passes through (0,0) and cuts the axes ...

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  16. A circle passes through origin and meets the axes at A and B so that (...

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  17. A rod PQ of length 2a sides with its ends on the axes the locus of the...

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  18. A line is at a distance c from origin and meets axes in A an dB. The l...

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  19. A right angled isosceles triangle is inscribed in the circle x^(2)+y^(...

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  20. If an equilateral triangle is inscribed in the circle x^(2)+y^(2)-6x-4...

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